The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are _ and _ respectively.

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Solution

Area of trapezium = h $\frac{(a + b)}{2}$ sq. units

= $\frac{1}{2}$ $\times$ (8 + 6) $\times$ 3 = 21 $c m^{2}$

Area of triangle = $\frac{1}{2}$ $\times$ b $\times$ h = $\frac{1}{2}$ $\times$ 14 $\times$ 3 = 21 $c m^{2}$

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The area of figure 1 (in cm2​) and area of figure 2 (in cm2​) are ___ and ___ respectively.

Area of trapezium = h (a+b)2sq. units = 12 × (8 + 6) × 3 = 21 cm2 Area of triangle = 12 × b × h = 12 × 14 × 3 = 21 cm2

The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are _ and _ respectively.

Area of trapezium = h $\frac{(a + b)}{2}$ sq. units

= $\frac{1}{2}$ $\times$ (8 + 6) $\times$ 3 = 21 $c m^{2}$

Area of triangle = $\frac{1}{2}$ $\times$ b $\times$ h = $\frac{1}{2}$ $\times$ 14 $\times$ 3 = 21 $c m^{2}$