The area of given figure is.

24 s q . u n i t s

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40 s q . u n i t s

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45 s q . u n i t s

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Solution

The correct option is C $45 s q . u n i t s$

Area of the figure = Area of A + Area of B + Area of C

Area of rectangle = $l e n g t h \times b r e a d t h$

A, B & C are rectangles
= $3 \times 6$ + $3 \times 3$ + $3 \times 6$
= $18 + 9 + 18$
= $45 s q . u n i t s$

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The area of given figure is.

The correct option is C 45 sq.units Area of the figure = Area of A + Area of B + Area of C Area of rectangle = length×breadth A, B & C are rectangles = 3×6 + 3×3 + 3×6 = 18+9+18 = 45 sq.units

The correct option is C $45 s q . u n i t s$

Area of the figure = Area of A + Area of B + Area of C

Area of rectangle = $l e n g t h \times b r e a d t h$

A, B & C are rectangles
= $3 \times 6$ + $3 \times 3$ + $3 \times 6$
= $18 + 9 + 18$
= $45 s q . u n i t s$