The area of one of the most common Indian sweets as per the given dimensions is $ ___~cm^2$.

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Solution

$Area of parallelogram = b a s e \times h e i g h t Area of kajubarfi (parallelogram) = (4 \times 3) c m^{2} = 12 c m^{2}$

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The area of one of the most common Indian sweets as per the given dimensions is \( ___~cm^2\).

Area of parallelogram=base×heightArea of kajubarfi (parallelogram)=(4×3) cm2=12 cm2

$Area of parallelogram = b a s e \times h e i g h t Area of kajubarfi (parallelogram) = (4 \times 3) c m^{2} = 12 c m^{2}$