The area of parallelogram represented by the vectors A=2^i+3^j and B=^i+4^j is
GivenA=2i+3jandB=i+4j .
Area of paralleogram AxB=(2i+3j+0k)×(i+4j+0k)
For i component we have,
(3×0)−(4×0)=0
For j component we have,
(0×2)−(1×0)=0
For k component we have,
(2×4)−(1×3)=5.
Now take the magnitude of this vector to find the area of the parallelogram:
A×B = Whole root of 02+02+52
= 0+0+5=5units