Question

The area of quadrilateral formed by joining the points $(-4,2),(1,-1),(4,1)$ and $(2,5)$ to nearest integer is _____.(in sq. units)

Answer 1

Let A, B, C, D be the points $(-4,2),(1,-1)$, (4, 1) and (2, 5) respectively.

Then the area of the quadrilateral ABCD

$=\frac{1}{2}\{-4\times -1-2\times 1+1\times 1-4\times -1+4\times 5-2\times 1+2\times 2\times -5\times -4\}$

$=\frac{1}{2}\{4-2+1+4+20-2+4+20\}$

$=\frac{49}{2}=24.5sq.units$