Question

The area of region bounded by curve $y=\cos 2x,$ line $x=0$ and $x=\frac{\pi }{3}$ is

• A. $\frac{2-\sqrt{3}}{4}$
• B. $\frac{\sqrt{3}}{4}$
• C. $\frac{4-\sqrt{3}}{4}$
• D. $\frac{\sqrt{3}-4}{4}$

Answer 1

The correct option is B $\frac{\sqrt{3}}{4}$

$y=\cos 2x$

${\int }_0^{\frac{\pi }{3}}\cos 2xdx$

$=\frac{1}{2}[\sin 2x{]}_0^{\frac{\pi }{3}}$

$=\frac{\sqrt{3}}{4}$ sq units