The area of rhombus whose diagonals are $16 c m, 24 c m$ .

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Solution

Diagonals of rhombus is $16 c m, 24 c m$
The area is given as $\frac{1}{2} (d_{1} \times d_{2}) \frac{1}{2} \times 16 \times 24 16 \times 12 = 192 c m^{2}$

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The area of rhombus whose diagonals are 16cm,24cm.

Diagonals of rhombus is 16cm,24cmThe area is given as 12(d1×d2)12×16×2416×12=192cm2

The area of rhombus whose diagonals are $16 c m, 24 c m$ .

Diagonals of rhombus is $16 c m, 24 c m$
The area is given as $\frac{1}{2} (d_{1} \times d_{2}) \frac{1}{2} \times 16 \times 24 16 \times 12 = 192 c m^{2}$