Given altitude of triangle exceeds base by 5 cm
Let the base be x cm
Therefore, altitude= (x + 5) cm
Area of triangle = (1/2) x base x altitude
150 = (1/2) × (x + 5) × (x)
multiplying x intobracket,
300 = x2 + 5x
x2 + 5x - 300 = 0
discriminant value
x= -b +/- root (b^2-4ac)
-------------------------
2a
-5 +root (25-4*1*(-300))
----------------------------
2a
-5 + root (1225)
----------------------
2
-5 +35 -5-35
-------- and -------
2 2
15 and -20
so only positive because length not be negative
Hence x = 15 cm
That is base = 15 cm
altitude = 15+5=20 cm
now area = 1/2 bh = 1/2 15*20 =150
correct