1
Question
The area of square field is 5184 meter square find the area of rectangular field whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth
The area of square field is 5184 meter square find the area of rectangular field whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth
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Solution
Given,
the area of square is=5184m²
s×s=5184
s²=5184
s=√5184
s=72
according to problem,
l=2x
b=x
we know that,
perimeter of square=perimeter
of rectangle
4s=2(l+b)
4×72=2(2x+x).
288=6x
x=288/6
x=48
from problem,
l=2x
=2×48
=96
b=x
=48
therefore length is 96
breadth is 48
area of rectangle = l × b
= 96 × 48
=4608 m²
the area of square is=5184m²
s×s=5184
s²=5184
s=√5184
s=72
according to problem,
l=2x
b=x
we know that,
perimeter of square=perimeter
of rectangle
4s=2(l+b)
4×72=2(2x+x).
288=6x
x=288/6
x=48
from problem,
l=2x
=2×48
=96
b=x
=48
therefore length is 96
breadth is 48
area of rectangle = l × b
= 96 × 48
=4608 m²
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