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Question

The area of square field is 5184 meter square find the area of rectangular field whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth

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Solution

Given,

the area of square is=5184m²

s×s=5184

s²=5184

s=√5184

s=72

according to problem,

l=2x

b=x
we know that,

perimeter of square=perimeter
of rectangle

4s=2(l+b)

4×72=2(2x+x).


288=6x

x=288/6


x=48

from problem,

l=2x

=2×48

=96

b=x

=48

therefore length is 96
breadth is 48

area of rectangle = l × b

= 96 × 48

=4608 m²

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