The area of the cardboard needed to make a box of size $25 c m \times 15 c m \times 8 c m$ will be

(a) $390 c m^{2}$

(b) $1390 c m^{2}$

(c) $2780 c m^{2}$

(d) $1000 c m^{2}$

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Solution

Size of box =25 cm, 15 cm, 8 cm

$∴$ Surface area =(lb+bh+hl)

$= 2 (25 \times 15 + 15 \times 8 + 8 \times 25) c m^{2}$

$= 2 (375 + 120 + 200) c m^{2} = 2 (695) = 1390 c m^{2}$

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Similar questions

Q. Tick (✓) the correct answer:
The area of the cardboard needed to make a box of size 25 cm × 15 cm × 8 cm will be
(a) 390 cm²
(b) 1390 cm²
(c) 2780 cm²
(d) 1000 cm²

Q. Find the area of the cardboard required to make a closed box of length 25 cm, 0.5 m and height 15 cm.

Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions $25 c m \times 20 c m$ $\times 5 c m$ and the smaller of dimensions $15 c m \times 12 c m \times 5 c m$ . For all the overlaps, $5 %$ of the total surface area is required extra. If the cost of the cardboard is $R s . 4$ for $1000 {c m}^{2}$ , find the cost of the cardboard required for supplying $250$ boxes of each kind.

Q. Shanti sweets stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions

25 c m \times 20 c m \times 5 c m

cm and the smaller of dimensions

15 c m \times 12 c m \times 5 c m

cm.For all the overlaps,

5

% of the total surface area is required extra. If the cost of the cardboard is

4

for

1000 c m^{2}

. find the cost of cardboard required for supplying

250

boxes of each kind.

Find the area of card board required to make a closed box of length 25 cm, breadth 10.5 cm and height 15 cm.

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The area of the cardboard needed to make a box of size 25cm×15cm×8cm will be (a) 390cm2 (b) 1390cm2 (c) 2780cm2 (d) 1000cm2

Size of box =25 cm, 15 cm, 8 cm ∴ Surface area =(lb+bh+hl) =2(25×15+15×8+8×25)cm2 =2(375+120+200)cm2=2(695)=1390cm2

The area of the cardboard needed to make a box of size $25 c m \times 15 c m \times 8 c m$ will be

(a) $390 c m^{2}$

(b) $1390 c m^{2}$

(c) $2780 c m^{2}$

(d) $1000 c m^{2}$

Size of box =25 cm, 15 cm, 8 cm

$∴$ Surface area =(lb+bh+hl)

$= 2 (25 \times 15 + 15 \times 8 + 8 \times 25) c m^{2}$

$= 2 (375 + 120 + 200) c m^{2} = 2 (695) = 1390 c m^{2}$