The area of the circle having its centre at (3, 4) and touching the line 5x + 12y - 11 = 0 is

16πsq units

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4πsq units

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12πsq units

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25πsq units

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Solution

The correct option is A
16πsq units

radius = perpendicular distance from centre to the tangent line

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Similar questions

Find the equation of the circle which has its centre at the point (3, 4) and touches the straight line $5 x + 12 y - 1 = 0$

(3, 4)

5 x + 12 y = 1

5 x + 12 y = 1

x^{2} + y^{2} - 6 x - 8 y + \frac{381}{169} = 0

5 x + 12 y - 10 = 0

5 x - 12 y - 40 = 0

C_{1}

6

C_{1}

C_{2}

C_{1}

8

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