The area of the circle x2-y2-16 exterior to the parabola y2-6 x isA- 4-34 -3B- 4-34 -3C- 4-38 -3D- 4-34 -3

The given equations are x2 + y2 = 16 … (1) y2 = 6x … (2) Area bounded by the circle and parabola Area of circle = π (r)2 = π (4)2 = 16π units Thus, t ...

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Byju's Answer

Standard XII

Mathematics

Area of Triangle Using Coordinates

The area of t...

Question

The area of the circle x² + y² = 16 exterior to the parabola y² = 6x is

A.

B.

C.

D.

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Solution

The given equations are

x² + y² = 16 … (1)

y² = 6x … (2)

Area bounded by the circle and parabola

Area of circle = π (r)²

= π (4)²

= 16π units

Thus, the correct answer is C.

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Choose the correct answer
The area of the circle $x^{2} + y^{2} = 16$ exterior to the parabola $y^{2} = 6 x$ is
(a) $\frac{4}{3} (4 π - \sqrt{3})$ (b) $\frac{4}{3} (4 π + \sqrt{3})$
(c) $\frac{4}{3} (8 π - \sqrt{3})$ (d) $\frac{4}{3} (8 π + \sqrt{3})$

Q. The area of the circle x² + y² = 16 enterior to the parabola y² = 6x is
(a)

\frac{4}{3} (4 π - \sqrt{3})

(b)

\frac{4}{3} (4 π + \sqrt{3})

(c)

\frac{4}{3} (8 π - \sqrt{3})

(d)

\frac{4}{3} (8 π + \sqrt{3})

Q. The area of the circle

x^{2} + y^{2} = 16

exterior to the parabola

y^{2} = 6 x

Q. Find the area of the circle x² + y² = 16 which is exterior to the parabola y² = 6x.

Q. The area included between the parabolas y² = 4x and x² = 4y is (in square units)
(a) 4/3
(b) 1/3
(c) 16/3
(d) 8/3

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The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is A. B. C. D.

The given equations are x2 + y2 = 16 … (1) y2 = 6x … (2) Area bounded by the circle and parabola Area of circle = π (r)2 = π (4)2 = 16π units Thus, the correct answer is C.

The area of the circle x² + y² = 16 exterior to the parabola y² = 6x is

A.

B.

C.

D.

The given equations are

x² + y² = 16 … (1)

y² = 6x … (2)

Area bounded by the circle and parabola

Area of circle = π (r)²

= π (4)²

= 16π units

Thus, the correct answer is C.