The area of the ends of the frustum are 183.35 and 103.13cm^{2 .}if the height of frustum be 11cm .Find the volume of frustum.

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Solution

Volume of frustum and area of ends relation is
V=(h/3)[A₁+A₂+(√(A₁A₂))]
V=(11/3)[103.13+183.25+(√(103.13×183.25))]
V=6167

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The area of the ends of the frustum are 183.35 and 103.13cm2 . if the height of frustum be 11cm .Find the volume of frustum.

Volume of frustum and area of ends relation is V=(h/3)*[A1+A2+(√(A1A2))] V=(11/3)*[103.13+183.25+(√(103.13×183.25))] V=6167

The area of the ends of the frustum are 183.35 and 103.13cm^{2 .}if the height of frustum be 11cm .Find the volume of frustum.

Volume of frustum and area of ends relation is
V=(h/3)[A₁+A₂+(√(A₁A₂))]
V=(11/3)[103.13+183.25+(√(103.13×183.25))]
V=6167