The area of the figure bounded by the curves $y = | x - 1 |$ and $y = 3 - | x |$ is

2 s q . u n i t s

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3 s q . u n i t s

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4 s q . u n i t s

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1 s q . u n i t s

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Solution

The correct option is A $4 s q . u n i t s$
Area of the curve figure bounded by curves $y = | x - 1 |$ and $y = 3 - | x |$
$y = x - 1 ⟶ (1) y = 1 - x ⟶ (2) y = 3 - x ⟶ (3) y = 3 + x ⟶ (4)$
For : (B)
$y = 1 - x y = 3 - x x = - 1 y = 2$
Area required = Area of rectangle ABCD
$= (A B) (A D)$
$= \sqrt{8} \times \sqrt{2} = 4 s q . u n i t s$

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