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Cross Product of Two Vectors

The area of t...

Question

The area of the figure formed by the points (-1,-1,1);(1,1,1) and their mirror images on the plane 3x + 2y + 4z + 1 = 0 is

\frac{5 \sqrt{33}}{29}

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\frac{4 \sqrt{33}}{29}

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\frac{20 \sqrt{33}}{27}

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\frac{20 \sqrt{33}}{29}

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Solution

The correct option is D $\frac{20 \sqrt{33}}{29}$

Req. area $= Δ P Q Q^{1} = 2 Δ P Q M = 2. \frac{1}{2} . Q M . P M$

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Similar questions

(3, 0, 0), (0, - 1, 0)

(0, 0, - 2)

3 x + 2 y + 4 z = 1

(2, 2, 1)

3 x + 2 y + 4 z + 1 = 0

2 x + y + 3 z + 2 = 0

(1, - 1, 1)

x + 2 y - 3 z + 1 = 0

3 x - 2 y + 4 z + 3 = 0

Q (0, - 1, - 3)

P

3 x - y + 4 z = 2

R

(3, - 1, - 2),

Δ P Q R

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