Question

The area of the given figure is ___$c{m}^2$​. $(\text{Both the ends are semi-circular and}\pi =\frac{22}{7})$

Answer 1

Area of the two semi-circles $=\frac{1}{2}\left(\pi r^2\right)+\frac{1}{2}\left(\pi r^2\right)=\pi \times r^2=\frac{22}{7}\times 7\times 7=154c{m}^2$

Width of the rectangular part = Diameter of the circular part = 14 cm

Area of rectangular part $=\text{length}\times \text{breadth}=(10\times 14)c{m}^2=140c{m}^2$

$\therefore$Total area $=$ Area of the two semi-circles $+$ Area of the rectangle $=(154+140)c{m}^2=294c{m}^2$​