Question

The area of the isosceles right angled triangle, which has hypotenuse length as $2$ is

• A. $1$
• B. $1.5$
• C. $\sqrt{2}$
• D. $\frac{1}{\sqrt{2}}$

Answer 1

The correct option is A $1$

The length of the hypotenuse of an isosceles triangle is $2$.

Since its isosceles, $x^2+x^2=4$, $x$ being the length of the congruent sides.

$\Rightarrow 2x^2=4$

$\Rightarrow x^2=2$

$\Rightarrow x=\sqrt{2}$

Area thus becomes $\frac{1}{2}\times \sqrt{2}\times \sqrt{2}=1$