The area of the largest triangle inscribed in a semicircle of radius R is

2 R^{2}

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\frac{3}{2} R^{2}

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\frac{1}{2} R^{2}

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R^{2}

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Solution

The correct option is C $R^{2}$
Area of $Δ = \frac{1}{2} \times R \times 2 R = R^{2}$

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In Triangle ABC the value of $\frac{r_{1} + r_{2}}{1 + c o s C}$ is always equal to

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