The area of the library in a school, having length 44m and width 25m needs to be doubled. What will be the new perimeter of the library?

224 m

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128 m

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124 m

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276 m

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Solution

The correct option is D 276 m
Length of the library = 44 m

Width of the library = 25 m

Length and width are doubled.

Hence, the new dimensions are 88m and 50m.

New perimeter = 2(length+width)

= 2(88+50) = 2(138) = 276 m

Hence, the new perimeter of the library = 276 m

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The area of the library in a school, having length 44m and width 25m needs to be doubled. What will be the new perimeter of the library?

The correct option is D 276 mLength of the library = 44 m Width of the library = 25 m Length and width are doubled. Hence, the new dimensions are 88m and 50m. New perimeter = 2(length+width) = 2(88+50) = 2(138) = 276 m Hence, the new perimeter of the library = 276 m

The correct option is D 276 m
Length of the library = 44 m

Width of the library = 25 m

Length and width are doubled.

Hence, the new dimensions are 88m and 50m.

New perimeter = 2(length+width)

= 2(88+50) = 2(138) = 276 m

Hence, the new perimeter of the library = 276 m