The area of the parallelogram formed by the points (1,1,1),(−2,4,1),(−1,5,5) and (2,2,5), is
A
81
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B
9
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C
36
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D
18
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Solution
The correct option is D 18 Assume points A,B,C,D of parallelogram ABCD be A(1,1,1),B(−2,4,1),C(−1,5,5) and D(2,2,5) →AB:3^i−3^j →AC:2^i−4^j−4^k →AB×→AC=(3^i−3^j)×(2^i−4^j−4^k) Area of parallelogram ABCD=|→AB×→AC|=18