Question

The area of the parallelogram whose adjacent sides are $\overline{P}=3\overline{i}+4\overline{j}$ , $\overline{Q}=-5\overline{i}+7\overline{j}$ is (in sq. units)

• A. 20.5
• B. 82
• C. 41
• D. 46

Answer 1

Answer: (C)

41

Area of parallelogram: $|\overrightarrow{P}\times \overrightarrow{Q}|=|3\times 7\hat{k}+4\times (-5)(-\hat{k})|=|41\hat{k}|=41$