The area of the quadrilateral formed by the tangent from the point (4,5) to the circle x2+y2−4x−2y−c=0 with a pair of radii joining the points of contacts of these tangents is 8 sq. units. The value of c is
A
12
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B
−1
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C
3
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D
11
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Solution
The correct options are C11 D−1 Given equation of circle is x2+y2−4x−2y−c=0
(−g,−f)=(2,1)
Radius =√g2+f2−c, h of sub tangent
Length of subtangent from point (x1,y1)=√x21+y21−4x1−2y1−c
Area of quadrilateral = length of subtangent x radius