The area of the quadrilateral formed by the tangents from the point (4, 5) to the circle x2+y2−4x−2y−11=0 with the pair of radii through the points of contact of the tangents is ;
A
4 sq. units
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B
8 sq. units
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C
6 sq. units
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D
None
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Solution
The correct option is B 8 sq. units Given equation of circle is x2+y2−4x−2y−11=0
Comparing it with general equation of circle i.e., x2+y2+2gx+2fy+c=0, we get,
(−g,−f)=(2,1)
Radius = √g2+f2−c=√4+1+11=4
Length of subtangent from point (4,5) = √42+52−42−2×5−11=2