The area of the rectangle (in $c m^{2}$ ) is:

6

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12

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18

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20

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Solution

The correct option is A $12$
In rectangle ABCD
Given One side = 4 cm so let AB =4 cm
Diagonal is 5 cm so AD = 5 cm
Now we know that triangle ABCD is a right angled triangle so
$A B^{2}$ + $B D^{2}$ = $A D^{2}$ (By pathagoras theoram )
Solving this equation we get BD = 3 cm
Area of rectangle = Base x height
4 x 3
=12 cm $^{2}$
So the correct answer is the option B

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The area of the rectangle (in cm2) is:

The area of the rectangle (in $c m^{2}$ ) is: