Question

The area of the region
$A=\left[\right(x,y):0\le y\le x|x|+1$ and $-1\le x\le 1]$ in sq . units is :

• A. $\frac{2}{3}$
• B. $\frac{1}{3}$
• C. $2$
• D. $\frac{4}{3}$

Answer 1

The correct option is C $2$

The graph is as follows:
${\int }_{-1}^0(-x^2+1)dx+{\int }_0^1(x^2+1)dx=2$