The area of the region bounded by the curve $| x | + | y | = 1$ is

1 s q . u n i t

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2 s q . u n i t

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\frac{1}{2} s q . u n i t

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4 s q . u n i t

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Solution

The correct option is B $2 s q . u n i t$
$a = 4 (\frac{1}{2} \times 1 \times 1) = 2 s q u n i t s$

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Similar questions

Using the method of integration find the area bounded by the curve

[Hint: the required region is bounded by lines x + y = 1, x – y = 1, – x + y = 1 and – x – y = 11]

| \begin{matrix} x \end{matrix} | = 1 - y^{2}

| \begin{matrix} x \end{matrix} | + | \begin{matrix} y \end{matrix} | = 1

y = x - 1

y = 3 - | x |

(y - 1)^{2} = 4 (x + 1)

y = x - 1

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