Question

The area of the region bounded by the curve $y=\sin x,x$-axis between the ordinates $x=0,x=2\pi$ is:

• A. 1 sq. units
• B. 2 sq. units
• C. 3 sq. units
• D. 4 sq. units

Answer 1

The correct option is D 4 sq. units

$4\stackrel{\pi /2}{\underset{2}{\int }}\sin xdx$
$=4\cos x{|}_0^{\pi /2}$
$=4squnits$