The area of the right angled $△$ $A O B$ is $16$ sec units. If $O$ is the origin and the coordinates of $A$ are $(8, 0)$ , what are the coordinates of $B$ ?

(0, 4)

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(0, 2)

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(- 1, 1)

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(0, \frac{1}{2})

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Solution

The correct option is A $(0, 4)$
Since, AOB is the right angled $Δ$ and A is on the
axis of x as its coordinates are (8, 0) Hence, B
should be on the axis of y
Let its coordinates be (0, y)
$∴ 16 = \frac{1}{2} \times 8 \times y$ or y = 4
Hence the co-ordinates of B are (0, 4)

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The area of the right angled △ AOB is 16 sec units. If O is the origin and the coordinates of A are (8,0), what are the coordinates of B?

The correct option is A (0,4)Since, AOB is the right angled Δ and A is on theaxis of x as its coordinates are (8, 0) Hence, Bshould be on the axis of yLet its coordinates be (0, y)∴16=12×8×y or y = 4Hence the co-ordinates of B are (0, 4)

The area of the right angled $△$ $A O B$ is $16$ sec units. If $O$ is the origin and the coordinates of $A$ are $(8, 0)$ , what are the coordinates of $B$ ?

The correct option is A $(0, 4)$
Since, AOB is the right angled $Δ$ and A is on the
axis of x as its coordinates are (8, 0) Hence, B
should be on the axis of y
Let its coordinates be (0, y)
$∴ 16 = \frac{1}{2} \times 8 \times y$ or y = 4
Hence the co-ordinates of B are (0, 4)