The area of the right angled triangle AOB is 16 sq. units. If 0 is the origin and the co-ordinates of A are (8, 0), what are the co-ordinates of B ?

(0,4)

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(0,2)

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(- 1, 1)

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(0, \frac{1}{2})

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Solution

The correct option is A (0,4)
Since, AOB is the right angled triangle and A is on the axis of x as its co-ordinates are (8, 0).
Hence, B should be on the axis of y.
Let its co-ordinates be (0, y).
∴16=1/2×8×y⟹y=4
Hence. the co-ordinates of B are (0, 4)

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The area of the right angled triangle AOB is 16 sq. units. If 0 is the origin and the co-ordinates of A are (8, 0), what are the co-ordinates of B ?

The correct option is A (0,4)Since, AOB is the right angled triangle and A is on the axis of x as its co-ordinates are (8, 0).Hence, B should be on the axis of y.Let its co-ordinates be (0, y).∴16=1/2×8×y⟹y=4∴16=12×8×y⟹y=4Hence. the co-ordinates of B are (0, 4)

The correct option is A (0,4)
Since, AOB is the right angled triangle and A is on the axis of x as its co-ordinates are (8, 0).
Hence, B should be on the axis of y.
Let its co-ordinates be (0, y).
∴16=1/2×8×y⟹y=4
Hence. the co-ordinates of B are (0, 4)