The area of the roof of the tree house is 5/2 sq yd. If the length of the roof is 3/2 yd, find the width of the roof.

\frac{5}{2}

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\frac{3}{5}

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\frac{5}{3}

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\frac{3}{2}

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Solution

The correct option is C $\frac{5}{3}$ yd
Area of the roof = $\frac{5}{2}$ sq yd

Area = Length $\times$ Width

Width = $\frac{A r e a}{L e n g t h}$

= $\frac{5}{2}$ $\div$ $\frac{3}{2}$

= $\frac{5}{2}$ $\times$ $\frac{2}{3}$

= $\frac{5}{3}$ yd

Hence, the width of the roof is $\frac{5}{3}$ m.

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