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Quadrilaterals

The area of t...

Question

The area of the shaded part in the given figure is $3.43 c m^{2}$
If true then enter $1$ and if false then enter $0$

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Solution

$A B C D i s a s q u a r e w i t h s i d e = 4 c m . ∴ a r A B C D = 4 \times 4 {c m}^{2} = 16 {c m}^{2} . N o w t h e h a l f c i r c l e s h a v e t h e d i a m e t e r s = \frac{1}{2} \times s i d e o f t h e s q u a r e = 4 c m s o t h e y a r e c o n g r u e n t & e q u a l i n a r e a . ∴ t h e i r r a d i i = \frac{4}{2} c m = 2 c m . S o A r h a l f c i r c l e s o f r a d i i 2 c m \times 2 = A r c i r c l e o f r a d i u s 2 c m . = π \times 2^{2} {c m}^{2} = \frac{22}{7} \times 4 {c m}^{2} . ∴ A r s q u a r e - A r h a l f c i r c l e s \times 2 = A r s h a d e d p o r t i o n . ⟹ A r s h a d e d p o r t i o n = (16 - \frac{22}{7} \times 4) {c m}^{2} . = 3.43 {c m}^{2} . A n s - A r s h a d e d p o r t i o n = 3.43 {c m}^{2} .$

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