Question

The area of the triangle $ABC$ as shown in the diagram is

• A. $\frac{1}{2}bc\mathrm{sq}.\mathrm{units}$
• B. $\frac{1}{2}ca\mathrm{sq}.\mathrm{units}$
• C. $\frac{1}{2}ab\mathrm{sq}.\mathrm{units}$

Answer 1

The correct option is C $\frac{1}{2}ab\mathrm{sq}.\mathrm{units}$

For the given triangle $ABC$ right angled at $B$.
We know that the area of a right triangle equals $\frac{1}{2}\times \text{base}\times \text{height}$.


In the given diagram $AC$ is the hypotenuse.
So, if we consider $BC$ as a bases,
$\Rightarrow AB$ is the height.
$\therefore$ Area $\Delta ABC=\frac{1}{2}\times b\times a$
Or $\frac{1}{2}\times a\times b$ sq. units