The area of the triangle ABC of the given dimensions is sq. m.

150

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 75
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ A B C = \frac{1}{2} \times B C \times A D$

$= \frac{1}{2} \times 10 \times 15$

= 75 sq. m

Suggest Corrections

Similar questions

Q. The area of the triangle ABC of the given dimensions is sq. m.

$A D$ is the median of the $△ A B C$ . If the area of $△ A B D = 10$ sq. units, find the area of $△ A B C$

Given a $△ A B F$ in which $B E = E F, B D = D E$ and $B C = C D$ . Area of $△ A B F = 64$ sq. units.

Find the area of $△ A B C$

In the given figure, triangles ABC and DEF are similar. The area of triangle ABC is 9 sq. cm and the area of triangle DEF is 16 sq. cm. If BC = 2.1 cm find the length of EF.

Q. The area of triangle ABC (in sq. units) is :

Join BYJU'S Learning Program

The area of the triangle ABC of the given dimensions is sq. m.

The correct option is B 75Area of triangle = 12× Base× Height ∴Area of ΔABC=12×BC×AD =12×10×15 = 75 sq. m

The correct option is B 75
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ A B C = \frac{1}{2} \times B C \times A D$

$= \frac{1}{2} \times 10 \times 15$

= 75 sq. m