The area of the triangle ABC of the given dimensions is sq. m.

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150

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125

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Solution

The correct option is A 75
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ A B C = \frac{1}{2} \times B C \times A D$

$= \frac{1}{2} \times 10 \times 15$

= 75 sq. m

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The area of the triangle ABC of the given dimensions is sq. m.

The correct option is A 75Area of triangle = 12× Base× Height ∴Area of ΔABC=12×BC×AD =12×10×15 = 75 sq. m

The correct option is A 75
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ A B C = \frac{1}{2} \times B C \times A D$

$= \frac{1}{2} \times 10 \times 15$

= 75 sq. m