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Byju's Answer
Standard XII
Mathematics
Two Point Form of a Line
The area of t...
Question
The area of the triangle formed by points
(
0
,
0
)
(
3
,
π
2
)
a
n
d
(
3
,
π
6
)
is
Open in App
Solution
Area of a triangle
=
Δ
=
1
2
∣
∣ ∣ ∣
∣
x
1
y
1
1
x
2
y
2
1
x
3
y
3
1
∣
∣ ∣ ∣
∣
=
1
2
∣
∣ ∣ ∣ ∣
∣
0
0
1
3
π
2
1
3
π
6
1
∣
∣ ∣ ∣ ∣
∣
=
1
2
[
0
−
0
+
1
(
3
π
6
−
3
π
2
)
]
=
1
2
(
3
π
6
−
9
π
6
)
=
1
2
×
−
6
π
6
=
−
π
2
But area is always positive.
Hence area of the triangle
=
π
2
sq.units
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