The area of the triangle formed by the intersection of a line parallel to x-axis and passing through P(h,k) with the lines y=x and x+y=12 is 4h2. If the locus of the point P is y=±Px+Q, then the value of P+Q is
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Solution
Area of triangle =12AB.BC=4h2∴AB=2|k−1|=AC⇒4h2=122(k−1)2⇒±2h=(k−1)