Area of Triangle with Coordinates of Vertices Given
The area of t...
Question
The area of the triangle formed by the line x + y = 3 and the angular bisectors of pair of straight lines x2−y2+2y=1 is
A
8 sq.units
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B
6 sq.units
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C
4 sq.units
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D
2 sq.units
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Solution
The correct option is D 2 sq.units x2−(y−1)2=0 is given pair of lines Vertices are (0,1),(0,3),(2,1) , Angular bisector is x(y-1) = 0 Area = 2 sq.units