The area of the triangle which is formed by the vertices ABC is

1 cm

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3 cm

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2 cm

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4 cm

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Solution

The correct option is C
2 cm

We can consider a square ABCD from this chart. And each side is equal to 2 cm.

The area of the triangle ABC will be the half of the area of this square ABCD.

We have known that the area of the square is = $a^{2}$ , where 'a' is the side of the square.

So, here the area is = $2^{2}$ = 4 $c m^{2}$

And hence the area of the triangle ABC will be = 2 cm.

OR, the area of a right-angled triangle is $\frac{1}{2} \times b \times h$ , here b=h=2 cm

So, the area becomes 2 cm.

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Similar questions

In given figure $△$ ABC and $△$ DEF are similar, BC = 3cm, EF = 4cm, and area of triangle ABC = 54 $c m^{2}$ . The area of $△$ DEF is ___ ${c m}^{2}$ .

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