The area of the triangle whose vertices are (0,1),(1,4) and (1,2) is ___ square units.
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is B 1
Formula for area of triangle is ∣∣∣12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]∣∣∣ where x1=0, y1=1, x2=1, y2=4, x3=1 and y3=2 Substitute the values, we get Area of triangle =∣∣∣12×[0(4−2)+1(2−1)+1(1−4)]∣∣∣ =∣∣∣12×[0+1−3]∣∣∣ =∣∣∣12×−2∣∣∣ =|−1| Area always in absolute value. So, area of the triangle is 1 square units.