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Question

The area of the triangle whose vertices are (−2,−3),(3,2), and (−1,−8) is:

A
5 square units.
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B
10 square units.
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C
15 square units.
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D
12 square units.
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Solution

The correct option is C 15 square units.
The area of triangle with given vertices can be obtained as:

k=12∣ ∣231321181∣ ∣

k=(1/2)[2(2+8)+3(3+1)+1(24+2)]
k=(1/2)[2(10)+3(4)+1(22)]k=(1/2)[20+1222]
k=(1/2)[42+12]
k=(1/2)(30)=15
So, the required area is 15 square units.

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