The area of the triangle whose vertices are (−2,−3),(3,2), and (−1,−8) is:
A
5 square units.
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B
10 square units.
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C
15 square units.
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D
12 square units.
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Solution
The correct option is C15 square units. The area of triangle with given vertices can be obtained as:
k=12∣∣
∣∣−2−31321−1−81∣∣
∣∣
⇒k=(1/2)[−2(2+8)+3(3+1)+1(−24+2)] ⇒k=(1/2)[−2(10)+3(4)+1(−22)]⇒k=(1/2)[−20+12−22] ⇒k=(1/2)[−42+12] ⇒k=(1/2)(−30)=−15
So, the required area is 15 square units.