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Question
The area of the triangle whose vertices are A(1,1),B(7,3) and C(12,2) is
The area of the triangle whose vertices are A(1,1),B(7,3) and C(12,2) is
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Solution
The correct option is A 8 square units
We know that the area of the triangle whose vertices are (x1,y1),(x2,y2), and (x3,y3) is 12|x1(y2−y3)+x2(y3−y1)+x3(y1−y2)|
∴Area =12[1(1)+7(1)+12(−2)]=−8, but area can not be negativeHence, area = 8 square units.
We know that the area of the triangle whose vertices are (x1,y1),(x2,y2), and (x3,y3) is 12|x1(y2−y3)+x2(y3−y1)+x3(y1−y2)|
∴
Area =12[1(1)+7(1)+12(−2)]=−8, but area can not be negative
Hence, area = 8 square units.
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