Question

The area of the triangle with vertices $A\left(z\right),B\left(iz\right)$ and $C(z+iz)$ is:

• A. $\frac{1}{2}|z+iz{|}^2$
• B. $1$
• C. $\frac{1}{2}$
• D. $\frac{1}{2}|z{|}^2$

Answer 1

The correct option is D $\frac{1}{2}|z{|}^2$


Area of $△ABC$
$=\frac{1}{2}\text{(area of square)}=\frac{1}{2}|z{|}^2$