Question

The area of the wrapping paper needed to wrap the given gift box of candy is

• A. 412 sq in
• B. 560 sq in
• C. 312 sq in

Answer 1

The correct option is A 412 sq in

The given box is in the shape of cuboid.

It contains 6 faces.

Each face is a rectangle.

The names of 3 sides are A, B and C.

The corresponding sides opposite to A, B and C are equal.

Surface area of side A = length $\times$ width

Length of side A = 10 in

Width of side A = 8 in

Surface area of A = 10 $\times$ 8 = 80 sq in



Surface area of side B = length $\times$ width

Length of side B = 8 in

Width of side B = 7 in

Surface area of B = 8 $\times$ 7 = 56 sq in



Surface area of side C = length $\times$ width

Length of side C = 10 in

Width of side C = 7 in

Surface area of C = 10 $\times$ 7 = 70 sq in


Total surface area = 2 $\times$(
surface area of side A+ surface area of side B + surface area of side C)

= 2(80 +56+ 70) = 2$\times$206 = 412

Hence, area of wrapping paper needed = 412 sq in.