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Question

The area of the wrapping paper needed to wrap the given gift box of candy is

A
412 sq in
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B
560 sq in
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C
312 sq in
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Solution

The correct option is A 412 sq inThe given box is in the shape of cuboid. It contains 6 faces. Each face is a rectangle. The names of 3 sides are A, B and C. The corresponding sides opposite to A, B and C are equal. Surface area of side A = length × width Length of side A = 10 in Width of side A = 8 in Surface area of A = 10 × 8 = 80 sq in Surface area of side B = length × width Length of side B = 8 in Width of side B = 7 in Surface area of B = 8 × 7 = 56 sq in Surface area of side C = length × width Length of side C = 10 in Width of side C = 7 in Surface area of C = 10 × 7 = 70 sq in Total surface area = 2 ×( surface area of side A+ surface area of side B + surface area of side C) = 2(80 +56+ 70) = 2×206 = 412 Hence, area of wrapping paper needed = 412 sq in.

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