The area of three adjacent faces of a cuboidal box are $120 c m^{2}$ , $72 c m^{2}$ and $60 c m^{2}$ , respectively. Its volume is

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Solution

Given $l b = 120 c m^{2}; b h = 72 c m^{2}; l h = 60 c m^{2}$
Volume $= l b h = \sqrt{l^{2} b^{2} h^{2}} = \sqrt{l b . b h . l h} = \sqrt{120 \times 72 \times 60} = 720 c m^{3}$

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The area of three adjacent faces of a cuboidal box are 120cm2, 72cm2 and 60cm2, respectively. Its volume is

Given lb=120cm2;bh=72cm2;lh=60cm2Volume =lbh=√l2b2h2=√lb.bh.lh=√120×72×60=720cm3

The area of three adjacent faces of a cuboidal box are $120 c m^{2}$ , $72 c m^{2}$ and $60 c m^{2}$ , respectively. Its volume is

Given $l b = 120 c m^{2}; b h = 72 c m^{2}; l h = 60 c m^{2}$
Volume $= l b h = \sqrt{l^{2} b^{2} h^{2}} = \sqrt{l b . b h . l h} = \sqrt{120 \times 72 \times 60} = 720 c m^{3}$