The area of three adjoining faces of the cuboid are $A, B a n d C$ respectively then its volume will be:

A B C

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\sqrt{A B C}

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A^{2} B^{2} C^{2}

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None of these

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Solution

The correct option is B $\sqrt{A B C}$
$l b = A, b h = 3, h l = C$
Now, $l b . b h . h l = A B C \Rightarrow {(l b h)}^{2} = A B C \Rightarrow l b h = \sqrt{A B C}$
Therefore, Volume $=$ $\sqrt{A B C}$

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