The area of trapezium whose parallel sides are 57 cm and 39 cm and the distance between them is 28 cm is

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Solution

The correct option is A

Let 'a' and 'b' be the parallel sides of the trapezium and 'h' be the height of the trapezium

Area of trapezium $= \frac{1}{2} (s u m o f p a r a l l e l s i d e s) \times h e i g h t$

$\Rightarrow \frac{1}{2} (a + b) \times h = \frac{1}{2} (57 + 39) \times 28 = 1344 c m^{2}$

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Find the area of the figure below which is made of two equal trapeziums. Two parallel sides of a trapezium are of lengths $57 c m$ and $39 c m$ . The distance between the parallel sides $A B$ and $F C$ is $28 c m$ .

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The area of trapezium whose parallel sides are 57 cm and 39 cm and the distance between them is 28 cm is

The correct option is A Let 'a' and 'b' be the parallel sides of the trapezium and 'h' be the height of the trapezium Area of trapezium =12(sum of parallel sides)×height ⇒12(a+b)×h=12(57+39)×28=1344 cm2