The area of triangle ACD in the given figure is :
50 m2
In △ABC,
Using Pythagoras theorem,
we get,
AC2=AB2+BC2 =82+62 =100.⇒AC=10 m
∵Area of triangle a triangle = 12×BASE×HEIGHT
∴Area of triangle ACD = 12×AC×CD as it is a right angled triangle
=12×10×10 =50 m2.