The area of triangle by a plane $2 x - 3 y + 4 z = 12$ with xy plane is :

12 s q u n i t s

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24 s q u n i t s

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6 s q u n i t s

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18 s q u n i t s

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Solution

The correct option is A $12 s q u n i t s$
On X-Y plane, z=0
$∴$ Plane 2x-3y+4z=12 becomes a line 2x-3y=12 in X-Y plane.
$\frac{x}{6} - \frac{y}{4} = 1$
Legs of Right triangle formed = 6, 4
$∴$ Area of right triangle = $\frac{1}{2} (6) (4) = 12$ sq units

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