Question

The area of triangle by a plane $2x-3y+4z=12$ with xy plane is :

• A. $12squnits$
• B. $24squnits$
• C. $6squnits$
• D. $18squnits$

Answer 1

The correct option is A $12squnits$

On X-Y plane, z=0

$\therefore$ Plane 2x-3y+4z=12 becomes a line 2x-3y=12 in X-Y plane.

$\frac{x}{6}-\frac{y}{4}=1$

Legs of Right triangle formed = 6, 4

$\therefore$ Area of right triangle = $\frac{1}{2}\left(6\right)\left(4\right)=12$ sq units