Question

The area of triangle formed by the lines x = 0, y = 0 and $\frac{x}{a}+\frac{y}{b}=1$, a and b are positive , is

• A. $ab$
• B. $\frac{ab}{2}$
• C. $2ab$
• D. $\frac{ab}{3}$

Answer 1

The correct option is B $\frac{ab}{2}$

The intersection of these lines are A(0,0), B(a,0), C(0,b). Hence we get a right angled triangle which is right angled at origin.
Length of perpendicular is b and length of base is a.
Area of the right angled triangle is
=$\frac{1}{2}\left(Perpendicular\right)\times \left(base\right)=\frac{1}{2}ab$.